ABC152 D - Handstand 2

提出

TLE

code: python

n = int(input())

pair = {}

for i in range(1, n+1):

for i in range(1, n+1):

for j in range(1, n+1):

ans = 0

for v in pair.values():

ans += len(v)

print(ans)

解答

code: python

n = int(input())

cnt = dict()

for top in range(10):

for bottom in range(10):

for i in range(1, n + 1):

result = 0

# 先頭が top、末尾が bottom の数が、N 以下にいくつあるのかを数える

for top in range(10):

for bottom in range(10):

print(result)

メモ

提出

code: python

n = int(input())

# (2, 2*2)

# (123, 3*1)

# (123456, 1*6)